Integrand size = 18, antiderivative size = 128 \[ \int \sqrt {f x} (a+b \text {arccosh}(c x))^2 \, dx=\frac {2 (f x)^{3/2} (a+b \text {arccosh}(c x))^2}{3 f}-\frac {8 b c (f x)^{5/2} \sqrt {1-c x} (a+b \text {arccosh}(c x)) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {5}{4},\frac {9}{4},c^2 x^2\right )}{15 f^2 \sqrt {-1+c x}}-\frac {16 b^2 c^2 (f x)^{7/2} \, _3F_2\left (1,\frac {7}{4},\frac {7}{4};\frac {9}{4},\frac {11}{4};c^2 x^2\right )}{105 f^3} \]
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Time = 0.22 (sec) , antiderivative size = 128, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.111, Rules used = {5883, 5949} \[ \int \sqrt {f x} (a+b \text {arccosh}(c x))^2 \, dx=-\frac {16 b^2 c^2 (f x)^{7/2} \, _3F_2\left (1,\frac {7}{4},\frac {7}{4};\frac {9}{4},\frac {11}{4};c^2 x^2\right )}{105 f^3}-\frac {8 b c \sqrt {1-c x} (f x)^{5/2} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {5}{4},\frac {9}{4},c^2 x^2\right ) (a+b \text {arccosh}(c x))}{15 f^2 \sqrt {c x-1}}+\frac {2 (f x)^{3/2} (a+b \text {arccosh}(c x))^2}{3 f} \]
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Rule 5883
Rule 5949
Rubi steps \begin{align*} \text {integral}& = \frac {2 (f x)^{3/2} (a+b \text {arccosh}(c x))^2}{3 f}-\frac {(4 b c) \int \frac {(f x)^{3/2} (a+b \text {arccosh}(c x))}{\sqrt {-1+c x} \sqrt {1+c x}} \, dx}{3 f} \\ & = \frac {2 (f x)^{3/2} (a+b \text {arccosh}(c x))^2}{3 f}-\frac {8 b c (f x)^{5/2} \sqrt {1-c x} (a+b \text {arccosh}(c x)) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {5}{4},\frac {9}{4},c^2 x^2\right )}{15 f^2 \sqrt {-1+c x}}-\frac {16 b^2 c^2 (f x)^{7/2} \, _3F_2\left (1,\frac {7}{4},\frac {7}{4};\frac {9}{4},\frac {11}{4};c^2 x^2\right )}{105 f^3} \\ \end{align*}
Time = 0.31 (sec) , antiderivative size = 118, normalized size of antiderivative = 0.92 \[ \int \sqrt {f x} (a+b \text {arccosh}(c x))^2 \, dx=\frac {2}{105} x \sqrt {f x} \left (35 (a+b \text {arccosh}(c x))^2-4 b c x \left (\frac {7 \sqrt {1-c^2 x^2} (a+b \text {arccosh}(c x)) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {5}{4},\frac {9}{4},c^2 x^2\right )}{\sqrt {-1+c x} \sqrt {1+c x}}+2 b c x \, _3F_2\left (1,\frac {7}{4},\frac {7}{4};\frac {9}{4},\frac {11}{4};c^2 x^2\right )\right )\right ) \]
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\[\int \left (a +b \,\operatorname {arccosh}\left (c x \right )\right )^{2} \sqrt {f x}d x\]
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\[ \int \sqrt {f x} (a+b \text {arccosh}(c x))^2 \, dx=\int { \sqrt {f x} {\left (b \operatorname {arcosh}\left (c x\right ) + a\right )}^{2} \,d x } \]
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\[ \int \sqrt {f x} (a+b \text {arccosh}(c x))^2 \, dx=\int \sqrt {f x} \left (a + b \operatorname {acosh}{\left (c x \right )}\right )^{2}\, dx \]
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\[ \int \sqrt {f x} (a+b \text {arccosh}(c x))^2 \, dx=\int { \sqrt {f x} {\left (b \operatorname {arcosh}\left (c x\right ) + a\right )}^{2} \,d x } \]
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Exception generated. \[ \int \sqrt {f x} (a+b \text {arccosh}(c x))^2 \, dx=\text {Exception raised: RuntimeError} \]
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Timed out. \[ \int \sqrt {f x} (a+b \text {arccosh}(c x))^2 \, dx=\int {\left (a+b\,\mathrm {acosh}\left (c\,x\right )\right )}^2\,\sqrt {f\,x} \,d x \]
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